In the drawing, if $BF=3$ and $DE=4$ and $\angle BCD = 90º$, find the lenght of $CF$
My try: I drew the segment $BE=CE$, because $AE$ is the angle bisector. After that i chased angles, and i found a lot of similar triangles, but after applying all the relations, i can't find the length of $CF$. I tried with sine and cosine law repeteadly, but it didn't work for me neither.