Simplify the following expressions to the simplest expression using De Morgan's theorem and Boolean algebra.





can anyone simplify it further and explain how you got there.Thanks in advance.

  • 1
    $\begingroup$ We have $AB\lor ABD=AB$ (absorption), and $ABD\lor (AB)'D=D$. So $AB\lor (AB)'D=AB\lor D$. $\endgroup$ – user10354138 Jun 3 at 8:49

It always helps to expand the terms so they include all variables .. and then reorganize, and recombine in a more efficient way, adding or removing duplicates as needed.

The key principle is:


$P = PQ + PQ'$

Starting from your second expression:






  • $\begingroup$ Thanks a lot!This was very helpful! $\endgroup$ – Jarvis Ferns Jun 3 at 12:04
  • $\begingroup$ @JarvisFerns You're welcome! :) $\endgroup$ – Bram28 Jun 3 at 12:28

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