Solve using simplex $$\text{ Max } z=4x_1+3x_2$$ $$\text{s.t } 2x_1+3x_2\leq 6 $$ $$-3x_1+2x_2\leq 3$$ $$2x_1 \leq 5$$ $$2x_1+x_2\leq 4$$ $$ x_1,x_2 \geq 0$$
I have solve it and got:
$So x_1 = 1.5, x_2 = 1 \text{ and } z=9$
One can see that some of the constrains are redundant as we need at most two equation for two unknowns. Can we have two "unused" slack variable in the basis? we just ignore them?