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a) Verify that for $x > 1$, $n \in \mathbb{N}$ the function $$P_n(x) = \frac{1}{\pi} \int_0 ^ \pi (x + \sqrt{x ^ 2- 1} \cos \phi) ^ n d \phi$$ is a polynomial of degree $n$ (the $n$th Legendre polynomial).

b) Show that $$P_n(x) = \frac{1}{\pi} \int_0 ^ \pi \frac{d\varphi}{(x - \sqrt{x ^ 2- 1}\cos \varphi) ^ n}.$$

I have solved the first part of the problem but I am stuck on the second part. I have tried making the substitution $r = \varphi - \pi$ in the second integral and using the oddity of $y = \cos x$ to bring the denominator to $(x + \sqrt{x ^ 2 - 1} \cos r) ^ n$, but I have little idea how to proceed from there. Can sombody help? Thanks in advance!

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1 Answer 1

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There must be something wrong. Or maybe I’m wrong.

Using substitution $t=\tan(\varphi/2)$ gives that $$\int_0^\pi \frac{d\,\varphi}{a+b\cos\varphi}=\frac{\pi}{\sqrt{a^2-b^2}}.$$ So in (b) we can get that $P_1(x)=1$ but in (a) we have obviously $P_1(x)=x$.

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  • $\begingroup$ I have just checked that you are probably right. $\endgroup$
    – Ziyang Guo
    Jun 2, 2019 at 2:11
  • $\begingroup$ Maybe there is an error in the problem. $\endgroup$
    – Ziyang Guo
    Jun 2, 2019 at 2:11

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