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I just want hint how to use the congruent condition..which involves an equation in X I guess

And I obtained one equation $$y^2=x (16+x)$$

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The condition $AC\simeq BC$ tells you that $\angle ABF=\angle BCD$. So, $ABF$ and $DCF$ are similar triangles. You get another equation from here.

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  • $\begingroup$ Thank you so much $\endgroup$ – learningstudent May 31 at 4:15
  • $\begingroup$ @learningstudent You are welcome. $\endgroup$ – Julian Mejia May 31 at 4:19
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Since $$\measuredangle BCD=\measuredangle CAB=\measuredangle B,$$ we obtain $$AB||CD$$ and from here we have the following system: $$y^2=x(x+16)$$ and $$\frac{y}{3}=\frac{x+10}{6}.$$ I got $$x=2.$$

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