Verifying my proof: "the equation $2x - 6y = 3$ has no integer solution to $x$ and $y$" Question:

Prove the equation $2x - 6y = 3$ has no integer solution to $x$ and $y$.

I need to verify my proof I think I did it correctly, but am not fully sure since I don't have solutions in my book. I basically proved by contradiction and assumed there was an integer solution for x or y. I then solved for $x $ and $y$ in $2x - 6y = 3$ getting $x = 3y + 3/2$ and $y = x/3 - 1/2$ .since both $x,y$ are not integers I said it contradicts that $x$ or $y$ had an integer solution, meaning the original statement was correct. Did I prove this right, or should I redo?
 A: Rewind to the point where you say $x=3y+3/2$. We rearrange this to $x-3y=3/2$, then note that since we have taken $x$ and $y$ to be integers, $x-3y$ is also an integer. But $3/2$ is not an integer, a contradiction.
A: Alternatively, you may write $$2x - 6y = 2(x-3y).$$  Since $x$ and $y$ are integers, so must be $x-3y$.  So $2(x-3y)$ must be an even integer, clearly being divisible by $2$.  But $3$ is odd.
A: Your proof, as it stands, is not correct. Some particular issues:


*

*You get to a point where $x = 3y + 3/2$ and $y = x/3 - 1/2$ and state that "since both $x,y$ are not integers..."; this assumes the conclusion that you're aiming for.

*It's not true that both $x$ and $y$ are not integers. You could have one of the two be an integer, and the other not be an integer. For example, $(0, -1/2)$ and $(3/2, 0)$ are both solutions with $x$ or $y$ integral, but not both.

*Its not convincing that $3y + 3/2$ is not an integer (and the point immediately above shows that that claim is not true!).

*Stylistically, your assumptions are not explicitly stated and there is no introduction to the proof. You haven't stated that you're assuming $(x, y)$ to be a pair of integers solving a particular equation. Therefore, it's not clear how the contradiction is reached; at a minimum, you need to form the negation of the statement and clearly include assumptions.
So unfortunately, this is not a properly written proof. But it can be fixed without too much work; here's an outline to follow:
1) Introduce the players. Say "We proceed by contradiction. Assume that $x, y$ are integers such that $2x - 6y = 3.$
2) Isolate one of the variables and get the contradiction. Perhaps "Then $x = 3y + \frac 3 2$. Since $3y$ is an integer (why?), the sum $3y + \frac 3 2$ is not an integer."
3) Tell the reader why this is a problem. "This contradicts the assumption that $x$ is an integer."
