# Can roots be $y$-intercepts for the quadratic function

I know this must be stupid question, but I was wondering why cannot a quadratic or any polynomial equation be in format of $$x=ay^2+by+c$$

and to find roots we set $$x=0$$.

In short, can the $$y$$ intercepts also be roots of quadratic equation?

I searched online and found that $$y$$ is imaginary and $$x$$ is real axis but I couldn't understand why polynomial equation when intercept $$y$$-axis and is solution to equation.

## migrated from physics.stackexchange.comMay 25 at 16:53

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Quadratic and polynomial equations CAN be written in terms of y rather than x. However, it is convention that we use x as the independent variable and y as the dependent one. thats why we always see $$y=ax^2+bx+c$$ rather than $$x=ay^2+by+c$$