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This is from my homework.

Let $Q_n$ be the graph with vertex set $\{1, 2, \ldots, n\}$. Two vertices are adjacent if and only if their greatest common divisor is $1$. Give the clique number of $Q_{10}$ and draw a maximum clique of it.

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    $\begingroup$ Just draw $Q_{10}$.. $\endgroup$ – Berci May 21 at 14:57
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    $\begingroup$ Hint: A maximum clique will be primes and $1$. $\endgroup$ – Thomas Andrews May 21 at 15:01
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The clique number is $5$. Note that there can be at most one even number in a clique, as two even numbers would have a common factor of $2$. Also note that $3$ and $9$ cannot be in the same clique as $3$ divides both. So not all odd numbers can be used. This gives us a maximum bound of $5$ numbers in a clique. $\{1, 2, 3, 5, 7 \}$ suffices to show that this is possible.

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