0
$\begingroup$

X is a uniform distribution on the interval (0,1). Y is a also uniform distribution on the interval (0,x). Its the only information that I could know. Then how can I calculate p(Y|x)? If you teach me, I will really appreciate that. Thanks for reading! Have a good day.

$\endgroup$
0
$\begingroup$

As the distribution of $Y$ is uniform, but dependent on $X$, the uniform PDF of $Y$ is actually $f_{Y|X} = \frac{1}{x}$ (as it is dependent on $X$).

Thus, $P(Y<y|X=x) = \int_0^y f_{Y|X}dy = \frac{y}{x}$

$\endgroup$
  • $\begingroup$ I really want to thank you for your help! Thank you for spending your time for me. Have a nice day! $\endgroup$ – jiyoung May 19 at 12:46

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.