a is a constant vector. Not really sure how to get the i,j and k components from this vector field.


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Write $\textbf{a}=a_1i+a_2j+a_3k$. Now what is $x\textbf{a}$?

  • 1
    $\begingroup$ I assume xa is (xa1)i + (xa2)j + (xa3)k? $\endgroup$ – sadiboos May 16 at 2:00
  • $\begingroup$ Yes, that is how scalar multiplication of the vector $\textbf{a}$ by the scalar $x$ works. Now do you see what the components are? $\endgroup$ – kccu May 16 at 3:22
  • $\begingroup$ yep ! thank you $\endgroup$ – sadiboos May 16 at 4:41

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