# How do i find the lcm [duplicate]

Qn: If the product of two integers is $$2^7 \cdot 3^8 \cdot 5^2 \cdot 7^{11}$$ and their greatest common divisor is $$2^3 \cdot 3^4 \cdot 5$$, what is their least common multiple?

I tried assuming that lcm is $$x$$ =. Then, Gcd $$\cdot x = 2^3 \cdot 3^4 \cdot 5x$$. And, product factors /Gcd $$x$$
## marked as duplicate by Bill Dubuque prime-numbers StackExchange.ready(function() { if (StackExchange.options.isMobile) return; $('.dupe-hammer-message-hover:not(.hover-bound)').each(function() { var$hover = $(this).addClass('hover-bound'),$msg = $hover.siblings('.dupe-hammer-message');$hover.hover( function() { $hover.showInfoMessage('', { messageElement:$msg.clone().show(), transient: false, position: { my: 'bottom left', at: 'top center', offsetTop: -7 }, dismissable: false, relativeToBody: true }); }, function() { StackExchange.helpers.removeMessages(); } ); }); }); May 11 at 15:02
• Hint: $lcm(a, b) = ab / gcd(a, b)$. – Borna Ghahnoosh May 11 at 14:54