Scott Steiner's WWE promo In Scott Steiner's WWE promo video, Scott mentions that in a three way match, everyone has a 33⅓ chance of winning, which is fair if you consider all fighters to be equal. But then, he proceeds to say that Kurt Angle cannot beat him so his chances of winning increase to 66⅔ %. How does that even work?
For example, in a three way situation, if I know in advance that one of the guys for sure will beat me, in a wrestling match how does the probability of my winning change?
I'm basically asking this, how does the probability of an event change when it makes it transition from a fair outcome to a biased/unfair outcome.
Example question that I framed:
One coin among three simultaneously tossed coins will always show heads. What is the probability of getting two heads?
 A: Let's model this "wrestling match" situation (I find the question quite amusing so I will try to give it justice; besides I think OP has an interest in math so might as well encourage it!)
Let's say we have wrestlers A, B, and C, and the match goes as this:
-You pick two wrestlers uniformly at random
-Then with some probability one wins over the other
-Then the remaining ones fight
Let's say P(A wins over B) = 0, P(B wins over A) = 1, and all other win probabilities are 1/2.
So, what is the probability that A (i.e. the guy that is for sure going to lose to B) wins? Well, for that to happen, it better be the case that B loses the first round, and then A wins the next one. So, the first round needs to be (B - C), which will be w.p. 1/3, then C wins (w.p. 1/2), and then A wins the next round (w.p. 1/2), and since these events are independent, the final probability is 1/12.
Let's also quickly disprove the claim that Bs chances are 2/3:
If the first match is A-B, then B wins w.p. 1, and then B wins w.p. 1/2
If the first match is A-C, then A wins w.p. 1/2, and then B wins w.p. 1
If the first match is A-C, then C wins w.p. 1/2, and then B wins w.p. 1/2
If the first match is B-C, then B wins w.p. 1/2, and then B wins w.p. 1 
Giving a total probability of 1/3(1/2 + 1/2 + 1/4 + 1/2) = 7/12, which is not that far away from 2/3 (8/12)
You can model many things around you using simple models like this; they are fun toy problems!
