Integral $\int_{a}^s\int_{a}^u\frac{1}{\sqrt{s-u}\sqrt{u-v}\sqrt{v-a}}dvdu$

Is it possible to get a closed form for $$\int_{a}^s\int_{a}^u\frac{1}{\sqrt{s-u}\sqrt{u-v}\sqrt{v-a}}dvdu\quad?$$

If we look at the simple integral it is related to Beta function, but for the multiple one not sure how to proceed.

• Hint: substitute $v=a+(u-a)w$ in the inner integral ($w\in(0,1)$ is a new variable). – metamorphy May 11 at 7:25

At the first one (variable $$v$$), performing the change of variable $$v-a=w^2$$ we have
$$\left.\int_a^u \frac{1}{\sqrt{u-v}\sqrt{v-a}}dv=2\int_0^{\sqrt{u-a}}\frac{1}{\sqrt{(u-a)-w^2}}dw=2\,\arcsin(w/\sqrt{u-a})\right|_0^{\sqrt{u-a}}=\pi$$
$$\int_a^s\int_a^u \frac{1}{\sqrt{s-u}\sqrt{u-v}\sqrt{v-a}}dvdu=\pi\int_a^s\frac{1}{\sqrt{s-u}}du=2\pi\,\sqrt{s-a}$$