Let $f(x) = ax^3 + bx^2 + cx + d$ be the polynomial with $a\in \mathbb Z.$
Suppose that $f(5) - f(4) =2019.$
Prove that $[f(7) - f (2)]$ is not a prime number.
Thanks all for help!
$f(5)-f(4) = 61a+9b+c = 2019$.
It is easy to find that $f(7)-f(2) = 335a+45b+5c = 335a+5(2019-61a) = 5(2019+6a)$. Note that $3\mid 2019$ and $3\mid 6a$, we have $2019+6a\ne \pm 1$.