# Polar area and do I need absolute value signs?

Imagine a curve such as $$r=\sqrt{\sin x}$$

The area over $$(0,\pi)$$ would be calculated as follows:

$$\int_0^{\pi}\frac{1}{2}\sqrt{\sin x}^2dx=\int_0^{\pi}\frac{1}{2}|{\sin x}|dx, not \int_0^{\pi}\frac{1}{2}{\sin x}dx$$ correct?

• Since $\sin x$ is nonnegative on $[0,\pi]$, you can remove the absolute value symbol. – John Thompson May 3 at 3:17
• I just realized that as i posted the question! Crap, i feel really stupid. Thanks though. – Roshan May 3 at 3:18