0
$\begingroup$

I was solving some algebra problems but I don't know how to do one of them. The task says "Determine three parametric equations of a segment HL, with H=(-3;5) and L=(2;-7) using a direction vector of module 2"

So far, I have determine the direction vector, which is (-3;5)-(2;-7)=(-5;12), and if it has to be of module 2 it would be (-10/13 ; 24/13). Now I don't know how to do the parametrizations.

$\endgroup$
  • $\begingroup$ Your point $\left(\dfrac{-10}{13},\dfrac{24}{13}\right)$ is not in the line $HL$ $\endgroup$ – Piquito May 3 at 0:13
  • $\begingroup$ So what shall I do? $\endgroup$ – AaronTBM May 3 at 0:48
0
$\begingroup$

If the length of the vector has to be 2, then, you can parameterize as: $(-3-(10/13)t,5+(24/13)t), 0\le t\le$(13/2)

$\endgroup$
  • $\begingroup$ For that parameterization, you want $-\frac{13}{2}\le t\le0$. $\endgroup$ – John Wayland Bales May 3 at 6:29

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.