The odds in favor of A winning a game of chess against B are 3:2. If 3 games are to be played, what are the odds: (a) in favor of A winning at least 2 games out of 3, (b) against A losing the first 2 games to B
It is known that the answer are:
I know this sentence The odds in favor of A winning a game of chess against B are 3:2. means: out of 5 games, A will ideally win 3 times and lose 2 times. In other words,the probability of A to win a game is 3/(3+2) = 3/5 but I do not understand how the answers (a) and (b) were calculated.