0
$\begingroup$

Find the area enclosed by $ρ=1+cos(\theta)$. I can not find the angle of the function to define the limits of the integrals.

This would be the graph of the function:

Graph of ρ=1+cos(\theta)

What I was trying to do, because of the symmetry of the function, was: $$2\int _0^α\int _0^{1+cos\left(\theta \right)}\:ρ\:dρd\theta$$

However, I can't correctly find the angle $α$. I would highly appreciate any suggestions.

$\endgroup$
0
$\begingroup$

$\alpha$ is the angle at which $r=1+\cos(\theta) =0$, therefore $$ A= 2\int _0^\pi \int _0^{1+\cos\left(\theta \right)}\:r\:\mathrm dr\mathrm d\theta$$

$\endgroup$
  • $\begingroup$ You are correct! Thank you very much $\endgroup$ – Monique Apr 29 at 20:54
  • $\begingroup$ Thank you for your attention. $\endgroup$ – Mohammad Riazi-Kermani Apr 29 at 20:58

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.