Let $(M,\omega)$ be a symplectic manifold, and $H : M \times [0,1] \to \mathbb{R}$ be a smooth time-dependent Hamiltonian on $M$. Then non degeneracy of $\omega$ implies the existence of a time-dependent Hamiltonian vector field $X_H^t$, uniquely defined by $$ \omega(X_H^t,.) = dH(.,t). $$ Consider the differential equation $$ \dot{x}(t) = X_H^t(x(t)). $$ If I am not mistaken, for any given $x \in M$, there exists a unique solution with initial condition $x(0) = x$ defined on an interval containing $0$ (which depends on $x$), provided that $H(.,t)$ has Lipschitz derivatives. This way, we obtain a one-parameter family $t \in I \to \phi_H^t(x) \in M$, where $I$ is the maximal interval of existence, that is the intersection of all intervals containing $0$ on which the solutions are defined. The family $\phi_H^t$ is called the Hamiltonian flow generated by $H$.
My question regarding the above is the following:
- In the literature, one never talks about the Lipschitz condition on $H(.,t)$, even when $M$ is compact, and moreover the time-$1$ maps $\phi_H^1$ (the Hamiltonian diffeomorphisms) are always considered without specifying if they even exist.
Is there a particular reason why the Lipschitz condition would not be necessary in this situation, and why the time-$1$ maps would always be defined ?
Thanks!