Two customers enter a $(\lambda_A=1,\lambda_S=2)-M/M/2$ in steady state.
Find the expected time that it will take for both to make through queue and have their service done.
My attempt: if this is a $M/M/1$ queue, then the time for the first person is $(\lambda_S-\lambda_A)=1$-exponential, and the other one is $\lambda_S=2$-exponential.
But I don't know how to proceed if this is $M/M/2$
Any help would be appreciated.