The question is:
For what real values of $p$ will the graph of the parabola $y=x^2-2px+p+1$ be on or above that of the line $y=-12x+5$?
Therefore, the $y$ value of the vertex of the parabola must be greater than or equal to the $y$ value of the line for corresponding values of $x$
An attempt to translate that would be:
$-12x+5 = -p^2+p+1$
With "$-p^2+p+1$" being the $y$ value of the vertex, as mentioned. However, this attempt doesn't really seem to open up any further steps.
What would be a more proper approach/solution for this problem?