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I am trying to solve the following question which is Ex3 from Arthur Engel, Problem Solving strategies. Here is the question: $\sum_{k=1}^n k^3 {n \choose k}$ and asks to find the sum. I am sincerely having a hard time trying to figure out how to solve it and get $n^2 (n+3)(2)^{n-3}$. I would really appreciate if someone could show the step-by-step process. Thank you!

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  • $\begingroup$ How about finding $\sum_{k=1}^n k^3\binom{n}k x^k$? $\endgroup$ – Lord Shark the Unknown Apr 21 '19 at 17:10
  • $\begingroup$ I am bad with combinatorics and that is why asked how to solve the above. I am trying to understand what techniques one uses and what knowledge is required to solve it. $\endgroup$ – Elvin Jafali Apr 21 '19 at 17:11
  • $\begingroup$ Well, my strategy would be to find $\sum_{k=1}^n k^3\binom{n}k x^k$ and then put $x=1$ into it. If you can't see how to do that sum, then think about $\sum_{k=1}^n k^2\binom{n}k x^k$. $\endgroup$ – Lord Shark the Unknown Apr 21 '19 at 17:17
  • $\begingroup$ @LordSharktheUnknown And how would you suggest they compute that polynomial? I don't think you've made things easier from their perspective. $\endgroup$ – kccu Apr 21 '19 at 17:33
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Let $k^3=k(k-1)(k-2)+ak(k-1)+ bk$

$\implies k=1,b=1$

$k=2,2^3=2a+2b\iff a=3$

Now for $k>2, $ $$k(k-1)(k-2)\binom nk=n(n-1)(n-2)\binom{n-3}{k-3}$$

Similarly $k\binom nk=?$

$k(k-1)\binom nk=?$

Finally use $(a+b)^m=\sum_{r=0}^n\binom mra^{m-r}b^r$

Set $a=b=1, m=n-3,n-2,n-1$

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