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I would like please some help with the following Geometry problem: We have a circle and two chords (which are perpendicular to each other). One chord is 3 cm and the other 4 cm. Calculate the circle's perimeter.

I think that we are able to find the circle's radius through Pythagoras' Theorem. Am I right?

Thank you very much in advance.

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  • $\begingroup$ Do the chords meet at a common endpoint? If so have 3-4-5 triangle to start with. $\endgroup$ – coffeemath Apr 20 at 20:01
  • $\begingroup$ Can you sketch it? How did you attempt? $\endgroup$ – Narasimham Apr 20 at 20:02
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    $\begingroup$ With "vertical Each other" you presumably mean they are perpendicular? $\endgroup$ – Wojowu Apr 20 at 20:17
  • $\begingroup$ If there is nothing known about the intersection point of the chords the only possible statement is that the circle perimeter is larger than $4\pi$ cm. $\endgroup$ – user Apr 20 at 20:46
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Diameter is 5 by Pythagoras thm and perimeter $5 \pi $ if the two segments connect at their common end-point.

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