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5y'= y(y+5) Hi, I'm blocked on this differential equation. The book suggests the separation method, but I don't know how to get the general equation in this specific case. Thanks to all. It's my first post thanks to anyone who considers it. Sorry, I don't know how to use MathJax.

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  • $\begingroup$ In this special case you can also use the methods of Bernoulli equations. Set $u=y^{-1}$, then $u'=-1-5u$ is a linear ODE. $\endgroup$ – LutzL Apr 19 at 13:55
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Write $$\frac{dy}{y(y+5)}=\frac{dx}{5}$$

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