Subset of combinations in larger set I am a biologist and not a real mathematician. Hence some of the answers featured here are sometimes too complicated. 
My question is:
I have set of 8 genes named PBX1,ESX1,PIM1,HBB,HBG,BCL11A,KLF4,GATA2
First I wanted to know how many different combinations of 6 I could make without caring about the order. I know now that this can be explained by:
(8x7x6x5x4x3)/(6x5x4x3x2x1) = 28 different combinations 
However, the second problem is a bit different. I want to know within these sets of 6 genes how frequently subsets of 4 or 3 or 2 genes are represented (again without caring about the order). 
for example:
how often does the combination (PBX1,ESX1,PIM1,HBB) occur within these larger sets of 6.
I hope someone is able to help. Please consider my lack of real mathematical knowledge in your answering.
Thanks in advance!!  
 A: The labels just make things look more complicated than they are.  Say the genes are $(g_1, g_2, \cdots, g_8)$.  Then, as you say, the number of ways to choose an ordered collection of $6$ of these is $$\binom 86=28$$
Having singled out, say, $g_1, g_2, g_3, g_4$ and insisting that that these be part of your collection, we now just have to choose $2$ from $g_5, g_6, g_7, g_8$.  The number of ways to do that is $$\binom 42=6$$
In general, if you select $i≤6$ genes and require them to be in your collection of $6$, then you have to choose $6-i$ from the remaining $8-i$ so the answer in that case would be $$\binom {8-i}{6-i}$$
A: So consider a fixed 4 tuple of genes, now we need to choose 2 more from the remaining 4 to make a six. So $\binom{4}{2}=6$ possible ways. So then out of the 28 different combinations, we have 6 of them containing the same 4-tuples. 
By a similar argument, for a fixed three genes, we have $\binom{5}{3}=10$ containing the same three tuples.
And then for a fixed two genes, we have $\binom{6}{4}=15$ containing the same two tuples!!
