# f(x) is invertible polynomial function of degree ‘n’ {n≥3} then f"(x) = 0 has exactly ‘n – 2’ distinct real roots if

$$f(x)$$ is invertible polynomial function of degree $$n\geq 3$$ then $$f''(x) = 0$$ has exactly $$n - 2$$ distinct real roots if

A)$$f′(x)=0$$ has $$n−1/2$$ distinct real roots

B)$$f′(x)=0$$ has $$n−1$$ distinct real roots

C)all the roots of $$f′(x)=0$$ are distinct

D)none of these

• Because f(x) is invertible function so all the roots of equation f'(x) = 0 are also the roots of equation f"(x) = 0 ⇒ If f'(x) = 0 has n−12 roots then number of roots of f"(x) = 0 equal to n−12+(n−12−1) =n−2 – user660100 Apr 17 at 11:28
• What's your question? – Matti P. Apr 17 at 11:33