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I need to find $X_a$ using this equation. I am having trouble working out how they got this answer. The question is $$ Y=X_a^{1/3} \left(\frac{w_a}{w_2} X_a \right)^{1/3} $$ The answer works out to be $X_a=Y^{3/2}\left(\frac{w_2}{w_a} \right)^{1/2}$

Click the link below to see my teachers working out. (If that helps) Here is my teachers working out...

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    $\begingroup$ What have you tried? The first phase would be to open the parentheses so that you can isolate $X_a$ (I mean: so that there is only one mention of $X_a$ in the right-hand-side of the equation) $\endgroup$ – Matti P. Apr 16 at 9:45
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    $\begingroup$ Cube both sides first $\endgroup$ – Claude Leibovici Apr 16 at 9:46
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$Y=X_a^{1/3}\left( \frac{w_a}{w_2}X_a\right)^{1/3}$

$Y^3=X_a\left( \frac{w_a}{w_2}X_a\right)=\frac{w_a}{w_2}(X_a)^2$

$(X_a)^2=Y^3\cdot \frac{w_2}{w_a}$

$X_a=Y^{3/2}\cdot \left(\frac{w_2}{w_a}\right)^{1/2}$

NOTE : you have a typo in your answer line

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