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Find $x$ if $|x-|3x+1||=4$

I got 4 values of $x$ out of which 2 are obsolete... Why so??

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closed as off-topic by user21820, Lee David Chung Lin, Ernie060, Arnaud D., José Carlos Santos Apr 29 at 13:34

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  • $\begingroup$ What does obsolete mean for a value ? $\endgroup$ – Rebellos Apr 15 at 19:02
  • $\begingroup$ They do not satisfy the equation $\endgroup$ – user664431 Apr 15 at 19:03
  • $\begingroup$ I dunno what they don't $\endgroup$ – user664431 Apr 15 at 19:03
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The equation implies $x - |3x+1| = \pm 4$. Two cases.

If $3x+1 > 0$ then you have $$ \begin{split} x - (3x+1) &\in \{\pm 4\}\\ -2x &\in \{-3,5\} \\ x &\in \{3/2, -5/2\} \end{split} $$ but only one of those satisfies the original assumption $3x+1>0 \iff x > -1/3$, so we end up with a solution $x = 3/2$.

Alternatively, $3x+1 \le 0 \iff x \le -1/3$, which implies $$ \begin{split} x + (3x+1) &\in \{\pm 4\}\\ 4x &\in \{3,-5\}\\ x &\in \{3/4, -5/4\} \end{split} $$ Can you finish the problem?

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  • $\begingroup$ Yeah... Thanks 😊😊😀😀 $\endgroup$ – user664431 Apr 15 at 19:07