0
$\begingroup$

(x + 2y + 1)Ux − (2x + y)Uy − (x − y − 1)U = 0

Would I go about this by doing the dx = dy = du format? If so how would I tackle the integrals to get the constants?

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.