Degree of $(y^{\prime\prime})^2(y^\prime)^2=x\sin(y^\prime)$

My try: since the highest order derivative is $y^{\prime\prime}$ and it's raised to power $2$, therefore I think that degree should be $2$.

But in my assignment the answer is given that since $\sin(y^\prime)$ would contain increasing powers of $y^\prime$, therefore degree isn't defined.

Whose answer is correct?


  • $\begingroup$ Depends on your Definition of degree. Care to share? $\endgroup$ – SK19 Apr 13 at 7:21
  • $\begingroup$ The order is the highest numbered derivative in the equation, while the degree is the highest power to which a derivative is raised. $\endgroup$ – Virad Gupta Apr 13 at 8:33

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