Let $\{N(t) \}_{t\geq0}$ be a Poisson process with rate $\lambda$. Suppose that each "arrival" is independently of type "$i$" with probability $p_i$. Then I know that the $\{N_i(t) \}$ are independent Poisson processes with rates $\lambda p_i$. The problem I'm having difficulty with is stated as follows:
Suppose cars arrive according to a Poisson process with rate $\lambda=3$ cars per minute, and each car is independently either Blue with probability 1/2, or Green with probability 1/3, or Red with probability 1/6.
Let $N(t)$ be the total number of cars that arrive by time t, and $N_R(t)$ the number of Red cars that arrive by time $t$.
*I wish to find $P(N_R(3)=2 \, | \, N(4) =4)$.
I would know how to solve this using independence if $t$ was equal in the condition $-$ i.e., $$ \begin{aligned} P(N_R(4)=2 \, | \, N(4) =4) &= \frac{P(N_R(4)=2 \, , \, N_B (4) + N_G(4) =2)}{P(N(4)=4)} \\ &= \frac{P(N_R(4)=2)P(N_B(4)+N_G(4)=2)}{P(N(4)=4)} \end{aligned} $$ however, I have not been able to figure out how to handle the different time. I've only been able to confidently get that, $$ P(N_R(3)=2 \, | \, N(4) =4) = P(N_R(3)=2 \, | \, N_R(4) + N_G(4)+N_B(4) =4) $$