2
$\begingroup$

Wikipedia cites the following text:https://epdf.tips/linear-functional-analysis.html (Page 79) which states that not every Hilbert space has an orthonormal basis. It states that an Hilbert space has an orthonormal basis iff its separable.

However, this site gives a proof using Zorn's Lemma which states that every Hilbert space has an orthonormal basis. The proof seems fine to me.

So now I am confused. Is there an orthonormal basis or not?

$\endgroup$
1
$\begingroup$

In the definition of orthonormal basis in the book:

Definition Let $\mathcal H$ be a Hilbert space and $\{e_n\}_{n\in \mathbb N}$ be an orthonormal sequence in $\mathcal H$. $\{ e_n\}_{n\in \mathbb N}$ is called an orthonormal basis if $\{ e_n : n\in \mathbb N\}^\perp = \{0\}$.

Note that $\{e_n\}_{n\in \mathbb N}$ is an orthonormal sequence if $\| e_n\| =1$ for all $n$ and $\langle e_i, e_j\rangle = 0$ for all $i\neq j$. That the index set is $\mathbb N$ is in the definition.

So in their definition, an orthonormal basis has to be countable. This definition is definitely not the one used (e.g.) in here.

Thus it is true that, using the definition in the book, that $\mathcal H$ has an orthonormal basis if and only if it is separable. A proof can be found here.

Example of Hilbert space without orthornormal basis (using your definition) can be found here.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.