Simplify the following expressions to the simplest expression using De Morgan’s theorem and Boolean algebra.
=¬(AD)+¬(¬(B+¬C)) =¬(AD)+(B+¬C) =¬(AD)+B+¬C
is the solution correct?
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I am reading this as:
$\neg (A \land \neg (B \lor \neg C) \land D)$
which by DeMorgan would be:
$\neg A \lor (B \lor \neg C) \lor \neg D$
$\neg A + B + \neg C + \neg D$