Im a student with not such a knowledge to solve equations with floor functions. I want to ask, if it is even possible and if it so, how is possible to prove this equation to be true.
- ⌊(n+m)/G⌋ = ⌊(2g-n-m)/G⌋-1
and where :
G= b^r g= b^r - 1
when needed , r and b can be replaced by any natural number
Edit1 : I only need to prove it when G= 2^r and g = 2^r-1 where r is variable
Edit2 : One of the variables, n or m can be fixed.