Hello, in this problem the person wrote dy/dt the same as x/y times dx/dt. I don't get how this works. Wouldn't you get (xdx)/(ydt)?
Also in this question I posted: Related Rates Calculus - Confused About What dx/dt, dy/dt and dx/dy mean
I was confused as to how dx/dy = y? One of the commenters said that when you do dx/dy you get x(y) = 1/2(y^2 - 1) but I have no idea how they got to that point or how that equals to y in the first place.
Any help is greatly appreciated. Thank you.