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Let $M$ is a von Neumann algebra equipped with state $\varphi$ , $\alpha$ $\in$ $Aut(M)$ preserving state $\varphi$, then does $\alpha$ extends to $\alpha_{1}:L^{1}(M,\varphi)\rightarrow L^{1}(M, \varphi)$?

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    $\begingroup$ The answer is yes if the automorphism is normal. Which i think is automatic if $\varphi$ is normal. $\endgroup$ Commented Mar 27, 2019 at 9:38

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The space L$^1(M,φ)$ is independent of the choice of the weight φ. It is known as the predual of M, and is also denoted by $M_*$.

In Sakai's approach to von Neumann algebras, von Neumann algebras are defined as C*-algebras that admit a predual and morphisms of von Neumann algebras are defined as morphisms of C*-algebras that admit a predual. So the answer to your question is tautologically true. See Sakai's book “C*-algebras and W*-algebras”.

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