# How can you further simplify a subtraction of two large factorials [closed]

100!-99! I am having a bit of difficulty with this question. Thanks in advance

## closed as off-topic by TomGrubb, mfl, Saad, Santana Afton, Lee David Chung LinMar 27 at 2:33

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• Hint: try writing the expansions of both terms – Alex Mar 27 at 0:35
• Welcome to MSE. Hint: $100!=100\times99!$ – J. W. Tanner Mar 27 at 0:36

You have $$100! - 99! = 100\times 99! - 99! = (100-1)99!$$
• $=99 \times 99!$ – J. W. Tanner Mar 27 at 0:45