# Automorphism group of a finite group [closed]

For which finite groups $$G$$ is $$\operatorname{Aut}(G)$$ isomorphic to a (non necessarily strict) subgroup of $$G$$?

## closed as off-topic by Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee TrainerMar 27 at 4:21

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shaun, Cesareo, clathratus, Lee David Chung Lin, Eevee Trainer
If this question can be reworded to fit the rules in the help center, please edit the question.

• Do you known any interesting examples? – lhf Mar 24 at 23:05
• $Aut(C_{2})$ is trivial, $Aut(S_{3})\cong S_{3}$. – Sylvain Julien Mar 25 at 6:02