How to solve the following logarithmic equation?

$$\log_2(x-5)=\log_5(2x+7)$$

Is there a way to solve this equation without drawing the graph and prove they "meet" in one point so the solution is unique? My first idea was to change their base according to the following formula: $$\log_b a = \frac{\log_x a}{\log_x b}$$ but I don't know what base to choose.

• It doesn't matter as long you end up with an equation where you have logs with the same base. Then take anti-logs. – herb steinberg Mar 23 '19 at 22:12

$$\log_2(x-5)=\log_5(2x+7)=y$$
So $$2^y=x-5$$ and $$5^y=2x+7$$. From the first equation, $$x=2^y+5$$. Substitute this in the second equation to get
$$5^y=2^{y+1}+17$$
We readily see that $$y=2$$ is a solution.
So $$x=2^2+5=9$$.