Let $f_n , f \in C({\Bbb R}/{\Bbb Z}, \Bbb C)$, show that if $f_n \to f$ uniformly, then $f_n \to f$ in the $L^2$ metric. where $C({\Bbb R}/{\Bbb Z},\Bbb C)$ is the space of complex-valued continuous Z-periodic functions
My work so far: $f_n \to f$ uniformly implies that $\forall \epsilon >0$, $\exists N > 0 $ such that $f_n(x) - f(x) < \epsilon \ \forall n>N, x\in \Bbb C$
In order to show that $f_n \to f$ in $L^2$, I need to show $\forall \epsilon > 0, \exists N>0 $ such that $ d_{L^2}(f_n,f)= (\int_{[0,1]} |f_n(x)-f(x)|dx)^{\frac{1}{2}} <\epsilon$
I am a bit stucked. I feel there should be something to do with the fact that these two functions are periodic but I am not sure.