10
$\begingroup$

Consider the Klein bottle (this can be done by making a quotient space). I want to give a proof of the following statement:

The Klein Bottle is homeomorphic to the union of two copies of a Möbius strip joined by a homeomorphism along their boundaries.

I know what such a Möbius band looks like and how we can obtain this also by a quotient map. I also know how to see the Klein bottle, but I don't understand that the given statement is correct. How do you construct such a homeomorphism explicitly?

$\endgroup$
10
$\begingroup$

Let's directly glue two Möbius strips into a Klein bottle.

  1. Take a Möbius strip and make its bottom wider:

mob to kel, step 1

  1. Make the rear part of the band like a half of a bottle, also the front part of the band like a tube.

mob to kel, step 2

  1. Take another Möbius strip and repeat steps 1 & 2 for the new one. Then glue new strip with the old one along their boundaries. Now we get a Klein bottle.

mob to kel, step 3

Therefore, a Klein bottle is homeomorphic to the glued Möbius strips.

$\endgroup$
7
$\begingroup$

Present a Klein bottle as a square with vertical edges identified in an orientation-reversing manner and horizontal edges identified in an orientation-preserving manner. Now make two horizontal cuts at one-third of the way up and two-thirds of the way up.

The middle third is one Möbius strip. Take the upper and lower thirds and glue them by the original horizontal identification. This is the other Möbius strip.

$\endgroup$
  • 1
    $\begingroup$ Thanks thats a very good idea to work with diagrams instead of mappings ;) $\endgroup$ – Crosscap Feb 26 '13 at 20:02

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.