Not a homework question. Just wanting to refresh my epsilon delta proofs, and came up with this - struggled for an hour, no idea where to start.

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    $\begingroup$ You might note that $e>2$ so $1/e < 1/2$. The function is strictly increasing for $x>0$, so evaluating at $x=1/2$ might be easier than evaluating at $x=1/e.$ $\endgroup$ – B. Goddard Mar 15 at 13:15
  • $\begingroup$ Yes it stops at $e^{x^x}$. $\endgroup$ – Daniel S Mar 15 at 13:16

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