Does the line passing through $(3,4,-1)$ which is normal to $x+4y-z = -2$, intersect any of the coordinate axes? [closed]

Does the line passing through $$(3,4,-1)$$ which is normal to $$x+4y-z = -2$$, intersect any of the coordinate axes?

I'm not sure how to go about this question. Any help would be greatly appreciated. Thank you in advance!

closed as off-topic by Saad, Vinyl_cape_jawa, Lee David Chung Lin, Parcly Taxel, ShaileshMar 16 at 4:06

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1 Answer

The line passing through $$(3,4,-1)$$ and normal to the plane $$x+4y-z = -2$$ has the following parametric equation: $$\begin{pmatrix}x\\y\\z\end{pmatrix}=\begin{pmatrix}3\\\color{blue}{4}\\\color{blue}{-1}\end{pmatrix}+\lambda\begin{pmatrix}1\\\color{blue}{4}\\\color{blue}{-1}\end{pmatrix}$$ It intersects a coordinate axis if two coordinates are (simultaneously) zero. Can you find a value of $$\lambda$$ for which this happens? Hint: look at the blue coordinates.

• Thanks, I get that, but is there a specific method to deduce this instead of simply using logic and observation? – Mayuri Gupta Mar 15 at 13:43
• If it's not that obivous, you can always look for points of intersection with the axes by solving the corresponding systems of equations - and see if they have a solution. In this case, setting $y=0$ and $z=0$ would yield the solution $\lambda=-1$. – StackTD Mar 15 at 13:47