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enter image description here I tried proving it by showing angles exy and eyx equal to edc and ecd respectively but I got no where . Is there any other approach I should consider

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  • $\begingroup$ Please edit title and body of the question to make it more readable. You could at least use GeoGebra to make a decent diagram. $\endgroup$ – Aretino Mar 15 at 8:17
  • $\begingroup$ HINT: use intercept theorem. $\endgroup$ – Aretino Mar 15 at 8:21
  • $\begingroup$ HINT: ...and a ruler. $\endgroup$ – TonyK Mar 15 at 9:59
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Because by similarity we obtain: $$\frac{FY}{YB}=\frac{EF}{BC}=\frac{EF}{AD}=\frac{FX}{XA}.$$

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