Let $R \neq \{0 \}$ be a commutative ring with identity. Suppose that $R$ has only finitely many minimal prime ideals $p_1,\dots , p_s.$ Then $$\sqrt {0} = \bigcap\limits_{i=1}^{s} p_i.$$
I know that $\sqrt 0 = \bigcap\limits_{p\text { prime}} p.$ But from here how do I prove the above theorem? Would anybody please help me regarding this.
Thank you very much.