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$$\begin{cases}xy + \frac{4}{xy} = 4 \\ 2x-y \; \;= 4 \end{cases}$$

I just defined y, but still can not proceed, please help.

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Hint:

Rearrange the first equation to find $(xy-2)^2=0\iff xy=2$

$$4=2x-y=2x-\dfrac2x$$

Rearrange to form a Quadratic equation in $x$

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  • $\begingroup$ Thanks for help! $\endgroup$
    – user640279
    Mar 10 '19 at 16:21

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