# How to find the modulus of vectors in this question (as seen in the image):

A problem I'm facing involves finding out the modulus of vectors. I now know how to solve and get the answer for 20. (a), but I am unsure how to do (b). I was thinking it would become |r-2r| = |-r| = |-5|. Is there any rule that would make it -|5| which would result in the answer being 5?

Also, I wanted to know how to solve for part (d) of the question. I know how to solve for (c) but did not understand how the vectors can be drawn for part (d).

For a)$$|r+5r|=|6r|=6|r|$$
b)$$|r-2r|=|-r|=|r|$$ c)$$|r+s|^2=|r|^2+|s|^2=…$$ d)$$s\cdot(r+s)=s\cdot r+|s|^2=0$$
for b, there is indeed a rule that is $$|\lambda \times v| = |\lambda|\times |v|$$ with $$\lambda = -1, |\lambda| = 1$$ .
For d, to draw it, you just need to set $$v = r + s$$. Then you can draw $$s$$ and $$v$$, and you know $$r = v - s$$