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I have two equations like $$\frac{\partial Y}{\partial x}=A(L-2x)\;\text{ at }(x,0)$$ And $$\frac{\partial Y}{\partial t}=0\;\text{ at }(0,0)$$ Is it possible to find out the real equation? (That is do there exist a unique function Y satisfying the above two initial conditions?)

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closed as unclear what you're asking by Saad, mrtaurho, Cesareo, José Carlos Santos, Learnmore Mar 9 at 15:07

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  • $\begingroup$ Are the 'prime' means partial derivatives , in that case please use the symbol $\endgroup$ – Bijayan Ray Mar 8 at 17:17
  • $\begingroup$ Yes,These are partial derivitives with respect to x and t respectively $\endgroup$ – Raihan Amin Mar 8 at 20:27
  • $\begingroup$ Some other informations I think are required too to find a unique function. $\endgroup$ – Bijayan Ray Mar 9 at 4:59
  • $\begingroup$ @Bijayan Ray Such as, $\endgroup$ – Raihan Amin Mar 9 at 14:20
  • $\begingroup$ Well just solve the Y at x,0 thinking it as a single function with the initial condition given in second equation, then for other x,t at arbitrary t , define Y such that the function is continuous or other such requirements are to be fulfilled like differentiability, intuitively speaking , there seems to exist many(at least some) such functions............ $\endgroup$ – Bijayan Ray Mar 9 at 17:48