0
$\begingroup$

Four points on a plane are given which are not collinear or all on one circle. How many straight lines and circles can be drawn in the plane so that they are equidistant from all four points?

If not collinear I believe that we cannot draw any lines, as the line could only possibly be equidistant from the other 3 at any given point on the line. It may be possible to be equidistant from all 4 if and only if we are only looking at specific point on the line

Not sure how I would go about drawing the circle

Any help would be appreciated

$\endgroup$
0

1 Answer 1

Reset to default
1
$\begingroup$

Hint: There are only two distances from the circle'a center $O$ to $A,B,C,D$. They are $r+d$ and $r-d$. One option is that $O$ is equidistant from $A$, $B$ and $C$.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .