A positive integer n does not have any 9 digits, it has four 8 digits, three 7 digits, two 6 digits and some other digits. If the sum of the digits of the numbeer n is 104 andthe sum of the digits of the number 2*n is 100, find the number of times the digit 5 appears in n.
Guys, my thoughts about the question above, are that in order for the sum of the digits of 2*n to be less than the sum of the digits of n, there have to be many digits inside it, which are larger than or equal to 5. However, this thought, did not lead me to the solution of the problem.
Can you guys please help me complete my thoughts, or, if they are wrong, can you please show me the correct method, of solving, this problem?
Thanking you in advance